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Question 1 of 5
1. Question
If the ages of P and R are added to twice the age of Q, the total becomes 59. If the ages of Q and R are added to thrice the age of P, the total becomes 68. And if the age of P is added to thrice the age of Q and thrice the age of R, the total becomes 108. What is the age of P?
Correct
Solution –
P + R + 2Q = 59 Q + R = 3P = 68 P + 3(Q+R) = 108 Solving the above two equations, we get P =12 years
Incorrect
Solution –
P + R + 2Q = 59 Q + R = 3P = 68 P + 3(Q+R) = 108 Solving the above two equations, we get P =12 years
Question 2 of 5
2. Question
Jay is twice old as Vijay and half as old as Sanjay. If the sum of Sanjay’s and Vijay’s ages is 85 years, what is Jay’s age in years?
Correct
Solution –
J : V : S = 2 : 1 : 4
Jay’s age = 2 / (1+4) × 85 = 34 years
Incorrect
Solution –
J : V : S = 2 : 1 : 4
Jay’s age = 2 / (1+4) × 85 = 34 years
Question 3 of 5
3. Question
Two years ago, a mother was four times as old as her daughter, 8 years hence, mother’s age will exceed her daughter’s age by 12 years. The ratio of the present ages of mother and daughter is
Correct
Solution –
Let the mother’s age 2 years ago be 4x and daughter’s age is 2 years ago be x (4x + 8) – (x + 8) =12 x = 4 Mother’s present age = 4x + 2 = 18 years and Daughter’s present age = x + 2 = 6 years Required Ration = 3:1
Incorrect
Solution –
Let the mother’s age 2 years ago be 4x and daughter’s age is 2 years ago be x (4x + 8) – (x + 8) =12 x = 4 Mother’s present age = 4x + 2 = 18 years and Daughter’s present age = x + 2 = 6 years Required Ration = 3:1
Question 4 of 5
4. Question
A father’s age is four times as much as the sum of the ages of his three children but 6 years hence his age will be only double the sum of their ages. Then the age of the father is
Correct
Solution –
Let the father’s age be x years and the sum of ages of children be y years
X = 4y …. (i)
Also, (x + 6) = 2(y + 6 + 6 + 6) ….. (ii)
(6 is added thrice for three children)
Solving (i) and (ii)
x = 60 years and y = 15 years
Incorrect
Solution –
Let the father’s age be x years and the sum of ages of children be y years
X = 4y …. (i)
Also, (x + 6) = 2(y + 6 + 6 + 6) ….. (ii)
(6 is added thrice for three children)
Solving (i) and (ii)
x = 60 years and y = 15 years
Question 5 of 5
5. Question
The sum of ages of a father and son is 45 years. Five years ago, the product of their ages was four times the father’s age at that time. The present age of the father is: